Physics, asked by ayush1204, 1 year ago

a player throw a ball at the angle of 30° with the horizontal with a velocity of 14 m/s if the point of projection is at a height of 12 m from the ground then calculate the distance up to which the ball is thrown by the players ?(g=10m/s)

Answers

Answered by jomintocon
3

It will follow a parabolic path.

Range is given as

R = u^2 Sin2x / g

= 14^2 * Sin60 / 9.8

= 17.32 m

Time taken to reach the ground in next part = sqrt(2H/g)

= sqrt(2 * 12 / 9.8)

= 1.56 s

x2 = u * t

= 14 * 1.56

= 21.84 m

Total distance = 21.84 + 17.32 = 39.16 m

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