a player throws a ball at an initial velocity of 36 m/s. calculate the maximum distance reached by the ball assuming the ball was catched at the same height it was released. if he wishes to throw the ball half the maximum distance in the shortest possible time compute the angle of elevation.
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V^2/a
36^2/9.8
=1296/9.8
=132.2448
Rounding off;
=132m
thank you
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Answer:
compute the angleof eevation
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