Question

A player throws a ball up with velocity 20m/s. Find the maximum height reached by the ball.

Answer 1

Answer:

Explanation:

v=u+at  

0=20−10t  

10t=20  

t=2

v^2=u^2+2as

0^2=20^2+2×(−10)×s

20s=400

s=20

Answer 2

Answer:

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