Question

a player throws a ball upwards with aninitial speed of 30 m s-1.how log does the ball take to return to the player's hands .take (g=10m s-2)​

Answer 1

Answer:

3 second

Explanation:

We are supplied with initial velocity of 30

So remove h by calculating the formula of

h=v^2÷2g we get height as ***45**

Now for time :: we have formula of

t=underroot of 2h/g

By calculating we get answer as =3 seconds