Question

A player transfers a momentum of 12 kg m/s to a ball of mass 400 g which is at rest. Find the work done on the ball.

Answer 1

Answer:

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Answer 2

Given :

Momentum = 12 Kg m/sec

Mass (m) = 400 g = 0.4 Kg

To Find :

Work Done

Solution :

If 'm' is the mass and 'v' is the velocity of the ball, then

Momentum of the ball = mv          

∴    mv       =    12 Kg m/sec

⇒   0.4×v   =    12

⇒          v   =    $\frac{12}{0.4}$

∴           v   =   30 m/sec

According to Work-Energy Theorem,

Work Done = Change in Kinetic Energy

                  = Final Kinetic Energy - Initial Kinetic Energy

As the ball was initially at rest, so, Initial Kinetic energy = 0

Work Done = Final Kinetic Energy

                   = $\frac{1}{2} mv^2$

                   = $\frac{1}{2}$ × mv × v

                   = $\frac{1}{2}$ × 12 × 30

                   = 180 J

∴ The work done on the ball is 180 J.