Question

A player x stands 50 yards away from y in the west. he moves 10 yards straight towards south and  then turns eastward going upto 50 yards, while y also comes down southward and meets x at the  same point. how far is y from his original position?

Answer 1

The answer is 10 yards.

Logic:

First of all player X is standing 50 yards away from player Y in West direction. Now player X turns towards south that is in left direction for 10 yards. And again turns towards east that is once again a left turn and walks for 50 yards. Now player X is actually perpendicular below to that of Y and at a distance of 10 yards because he has already compensated the 50 yards distance that was initially made in the westward direction.

Now in the question it is said that Y also comes down and meet X that means Y move down in South direction for 10 yards.