Question

A playground is 30 m longer than it is wide. If its perimeter is 300 m, what is its area?
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Answer 1

Answer :

5400m²

Step-by-step explanation:

let wide=x

then length = 30+x

Perimeter =300m

> 2(l+b)=300

2(30+x+x)=300m

60+4x =300

4x=240

x=60

Henceforth

length =90m

width =60m

Finally area =l*b

Area=90*60

=5400m²

Answer 2

†GIVEN†

• Length of rectangle = 30m longer than width.
• Perimeter of rectangle = 300m.

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†TO FIND†

• The area of rectangular playground.

______________________

†SOLUTION†

Let ,

Width of rectangle = x

Length of rectangle = x+30

$\color{black}\bold</p><p>{A/q\:Perimeter = 300}$

$\color{black}\bold</p><p>{ \implies \: 2(x + x + 30) = 300}$

$\color{black}\bold</p><p>{ \implies \:2( 2x + 30) = 300}$

$\color{black}\bold</p><p>{ \implies4x + 60 = 300}$

$\color{black}\bold</p><p>{ \implies4x = 240}$

$\color{black}\bold</p><p>{ \implies \: x = 60}$

${ \boxed{∵x = 60}}</p><p>$

By putting the value of x

Width = x = 60m

Length = x+30 = 60 + 30 = 90m

∴ Area of rectangle = (Length × Width)m²

$\color{black}\bold</p><p>{ =(60 \times 90) {m}^{2} }$

$\color{black}\bold</p><p>{ = 5400 {m}^{2} }$

${ \boxed{∵Area \: of \: playground \: = 5400 {m}^{2} }}</p><p>$