A playground is 460m long and 250 m broad Find the
a) cost of levelling at Rs
16 per 100 sq.m
b) number of rounds along the boundary one should take to run 4 km
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₹18400 and 2.82 rounds.
Step-by-step explanation:
L of the playground = 460m
B of the playground = 250m
therefore, perimeter of the playground =>
2(460+250)m
= 2(710)m
= 1420m
therefore, area of the playground =
(460 × 250)m²
= 115000m²
Now, Question number (a) →
cost of levelling 100m² = ₹16
cost of levelling 1m² = ₹ 16/100
therefore, cost of levelling 115000m² = ₹(16/100)×115000
= ₹18400
Now, Question Number (b) →
Perimeter of the playground = 1420m
Number of such perimeters in 4km/4000m =
(4000/1420)
= 2.82 (approx) such perimeters/ rounds of that perimeter to cover a distance of 4km.
hope it helped
thanks !!
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