Math, asked by alamshams452, 2 months ago


A playground is marked with 10 10 grid as shown in fig. Three parrots are sitting at
points P, (3, 4).P,(6, 7).P,9,4) respectively. A koel'K'joins them and sit somewhere
in the triangular region described by AP PP,
10
192
2
10
Consider O as origin, answer questions (i) to (v).
Ifkoel sit exactly on mid-point of P,P, what are its coordinates ?
(a) G
(b) (6,4)
(c) (3)
(d) (6,5)
(11)
Ifkoel sits at centroid of AP,P.P.The following point best describes its location.
(a) (6,5)
(b) (6,4)
(c) (3,9)
(iii) Distance of koel 'K' from P, in position (i) mentioned above is given by
(a) 9 units
(b) 6 units
(c) 3 units
(d) 12 units
(iv) Distance ofkoel 'K' from P, in position (ii) mentioned above is given by
(a) 3 units
(b) 1 unit
(c) 2 units
(d) 5 units
(v) Ifkoel sits at a point which is equidistant from all three parrots, then position of
koel is actually
(a) In centre of A
(b) circum centre of A
(c) Centroid of D
(d) orthocenter of​

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Answers

Answered by amitnrw
9

Given : Three parrots are sitting at points P₁ (3, 4), P₂(6, 7), P₃(9,4)

To Find : If koel sit exactly on mid-point of  P₁ (3, 4), P₃(9,4)

what are its coordinates

If koel sit at centroid of ΔP₁P₂P₃

what are its coordinates

Solution:

P₁ (3, 4), P₃(9,4)

koel sit exactly on mid-point of  P₁ (3, 4), P₃(9,4)

coordinates = ( 3 + 9)/2 , (4 + 4)/2

= 6 , 4

koel sit at centroid of ΔP₁P₂P₃

P₁ (3, 4), P₂(6, 7), P₃(9,4)

centroid = ( 3 + 6 + 9)/3 , ( 4 + 7 + 4)/3

= 6 , 5

Distance of  P₁ (3, 4) from (6 ,4 )

= √(6- 3)² + (4 - 4)²

= √3² + 0

= 3  unit

Distance of  P₂(6, 7) from (6 ,4 )

= √(6- 6)² + (6 - 4)²

= √0+3²

= 3  unit

Circumcenter of triangle is at Equal distance from all vertex

Learn More:

state mid-point theorm and find answer for the question - Brainly.in

https://brainly.in/question/33571911

Answered by Anonymous
60

Answer :-

P₁ (3, 4), P₃(9,4)

koel sit exactly on mid-point of  P₁ (3, 4), P₃(9,4)

coordinates = ( 3 + 9)/2 , (4 + 4)/2

= 6 , 4

koel sit at centroid of ΔP₁P₂P₃

P₁ (3, 4), P₂(6, 7), P₃(9,4)

centroid = ( 3 + 6 + 9)/3 , ( 4 + 7 + 4)/3

= 6 , 5

Distance of  P₁ (3, 4) from (6 ,4 )

= √(6- 3)² + (4 - 4)²

= √3² + 0

= 3  unit

Distance of  P₂(6, 7) from (6 ,4 )

= √(6- 6)² + (6 - 4)²

= √0+3²

= 3  unit

Circumcenter of triangle is at Equal distance from all vertex

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