a
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Hey mate!
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here is your answer:
total number of outcomes=4{ (HH);(TT);(TH);(HT)}
1. favourable outcomes =2
probability of getting one head=2/4=1/2
2. favourable outcomes =3
probability of getting atmost two head =3/4
3. favourable outcomes=2
probability of getting one tail=2/4=1/2
4. favourable outcomes =0
probability of getting more than two heads=0/4=0
5. favourable outcomes =3
probability of getting at least one tail=3/4
6. favourable outcomes =3
probability of getting less than 3 tails=3/4
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hope it helped ^_^
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