Question

a plot measures 120 m×100 m .two cross paths of 10 m width are constructed at right angles through the center of field and parell to the side of plot . find the area of path

Answer 1

Solution :-

If two cross roads each of width 'W' unit, run at right angles through the centre of rectangular path of length 'l' units and breadth 'b' units, then

the area of total path =(width of path)(length of the park + breadth of the park -width of path)

=w(l+b-w)

Using this formula

From given data

l=120m

b=100m

w=10m

Area of the total path=w(l+b-w)

=10(120+100-10)

=10×210

=2100 square meters

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@GauravSaxena01

Answer 2

Answer ⇒ Area of the Cross Paths is 2100 m².

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Step-by-step explanation ⇒

Area of the Total Plot = 120 × 100 = 12000 m²

Now, Area of the Cross paths can be calculated by subtracting the inner area from the total area.

∴ Inner Area = (120 - 10) × (100 - 10)

  = 110 × 90

  = 9900  m².

∴ Area of the Cross Paths = 12000 - 9900

 = 2100 m².

Hence, the Area of the Cross-Paths is 2100 m².

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Hope it helps.