Math, asked by sravanthigowri87, 20 days ago

A plot of land is in the shape of a sector of a circle of 28m.If the sectorial angle (central angle) is 60 degrees,find the area and the perimeter of the plot.​

Answers

Answered by sunitapandeyvaranasi
0

Step-by-step explanation:

Answer: The area of the land is 410.67 m² and the perimeter is 85.33 m. Step-by-step explanation: The sectorial angle of the sector of the circle is 60°

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Answered by bhagyashreechowdhury
0

The area of the plot is 410.67 m².

The perimeter of the plot is 85.34 m.

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Let's understand a few concepts:

To calculate the area of a sector when the value of theta is given in degrees we will use the following formula:

\boxed{\bold{Area \:of\:a\:sector= \frac{\theta}{360\°}\times \pi r^2 }}

To calculate the length of the arc of a sector when theta is given in degrees we will use the following formula:

\boxed{\bold{Length \:of\:arc= \frac{\theta}{360\°}\times2 \pi r }}

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Let's solve the given problem:

The radius of the sector-shaped plot of land (r) = 28 m

The central angle (θ) = 60°

Finding the area of the sector-shaped the plot of land:

The area of the plot of land in the shape of a sector is,

= \frac{60\°}{360\°} \times \frac{22}{7} \times 28^2

= \frac{1}{6} \times \frac{22}{7} \times 28^2

= \frac{17248}{42}

= \bold{410.67\:m^2}

Finding the perimeter of the sector-shaped the plot of land:

The perimeter of the plot of land in the shape of a sector is,

= [Arc length] + [Radius] + [Radius]

= [\frac{60\°}{360\°} \times2 \times  \frac{22}{7} \times 28] + 28 + 28

= [\frac{1}{6} \times 2\times  \frac{22}{7} \times 28}] + 56

= [\frac{1}{3} \times  22 \times 4}] + 56

= 29.34 + 56

= \bold{85.34\:m}

Thus, the area and the perimeter of the plot is 410.67 m² and 85.34 m respectively.

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