Question

A PMMC meter carries maximum current 15mA when a p.d. of 0.75 V is applied across it. How will you convert it into voltmeter for measuring 150 volts ?​

Answer 1

Answer:

Given : V=750×10

−3

V;

I

g

=15×10

−3

A and I=25A

Using, a=

I

g

y

=

15×10

−3

750×10

−3

=50Ω

I

g

=

S+a

S

×I

15×10

−3

=(

S+50

S

)×25

∴S=0.03Ω