Question

a point A is at a distance of root 29 from the point B(6,-3).find the coordinates of A, if it's ordinate is half of its abcissa​

Answer 1

Answer:

(4,2) & (16/5,8/5)

distance between A and B is

$\sqrt{29 }$

let suppose A coordinator are (x,y)

and given is y=x/2 and B(6,-3)

now from distance formula

$\sqrt{ {(x - 6)}^{2} + {(y + 3)}^{2} } = \sqrt{29}$

put x=2y

$5 {y}^{2} - 18y + 16 = 0 \\ y = 2 \: or \: y = \frac{8}{5} \\ x = 4 \: or \: x = \frac{16}{5}$

Answer 2

Answer:

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