Question

A point A is at a distance of under root 10 from the point (4,3).Find the co-ordinate of point A. if it's ordinate is twice of its abscissa.

Answer 1

ain, given, the point P is at a distance of root of 10 from the points (4,3)

=> √{(2 - a)2 + (3 - 2a)2 } = √10

=> (2 - a)2 + (3 - 2a)2  = 10

=> (4 + a2 - 4a) + (9 + 4a2 - 12a) = 10

=> 4 + a2 - 4a + 9 + 4a2 - 12a = 10

=> 13 + 5a2 - 16a = 10

=> 5a2 - 16a + 13 - 10 = 0

=> 5a2 - 16a + 3 = 0

=> 5a2 - 15a - a + 3 = 0

=>5a(a - 3) - 1(a - 3) = 0

=> (a - 3)*(5a - 1) = 0

=> a = 3, 1/5

So, 2a = 6, 3/5

Hence, the point is either (3, 6) or (1/5, 6/5)

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Answer 2

Answer:

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Step-by-step explanation:

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