Question

A point B is 25 cm from the centre O of the circle. The length of the tangent drawn from B to the circle is 24 cm. Find the radius of the circle​

Answer 1

Answer :-

7cm

STEP-BY-STEP EXPLANATION :-

Refer the image first

From right angled ∆AOB

➡ OB² = OA² + AB²

➡ (25)² = OA² + (24)²

➡ 625 = OA² + 576

➡ OA² = 625 - 576

➡ OA² = 49 = 7²

➡ OA = 7

Hence, The radius of the circle is 7 cm

Answer 2

Given,

OB = 25

OA =?

AB = 24

${ob}^{2} = {oa}^{2} + {ob}^{2}$

${25}^{2} = {oa}^{2} + {24}^{2}$

$625 = {oa}^{2} + 576$

${oa}^{2} = 625 - 576$

${oa}^{2} = 49$

${oa}^{2} = {7}^{2}$

$oa = 7$