a point C lies between two points A and B such that AC =BC, then prove that AC = 1 2 AB. Explain by drawing the figure. (ii) In the figure, AC = DC, CB = CE, show that AB = DE.
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We have AC = DC ...(1) [Given]
And CB • CE...(2) [Given]
Now, by axiom 2, if equals are added to equals, the wholes are equal.
Adding (1) and (2).
we get AC + CB = DC + CE
Hence, AB = DE
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