A point charge +10 μC is a distance 5 cm directly above the centre of a square of side 10 cm, as shown. What is the magnitude of the electric flux through the square?
Answers
Answered by
5
Answer: The electric flux through the square is 1.88 × 105 N m² C⁻¹
Explanation:
Step 1: Finding closed surface for the application of Gauss Law
According to Gauss’s theorem for a cube, total electric flux is through all its six faces.
Ф total = q / €₀
The square can be considered as one face of a cube of edge 10cm with a centre where charge q is placed.
Step 2: Finding Flux through one face or square
As the charge is placed symmetrically to each face of the cube, thus electric flux passing through each face is equal.
the electric flux through one face of the cube can be written as
Ф₁= Ф total / 6
= q/ 6€₀
Ф₁ = 10×10⁻⁶C / 6 × 8.854 ×10⁻¹² N⁻¹m⁻²C²
= 1.88×10⁵ Nm²C⁻¹
Therefore, electric flux through the square is 1.88×10⁵ Nm²C⁻¹
Similar questions