Question

A point charge 50uC is located in the XY plane at the point of position vector 2î+3j. What is the electric field at point of position vector 8î+5j

Answer 1

Explanation:

Aloha !

-> 2î+3j

Magnitude:-

=√( 2²)+(3)²

=√4+9

=√13

->8î+5j

Magnitude:-

=√(8)²+(5)²

=√64+25

=√89

Sum of magnitudes= √102

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@ Twilight Astro ✌️☺️

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Answer 2

Answer:

hey mate ✌✌

using formula of addition of vector,

position vector 2i cap + 3j cap

and 8i cap + 5i cap

50 = 10i cap + 8j cap

therefore,

the electric field will be root 12 + root 89

= root 101 .

Explanation:

hope it helps ✔✔