Question

A point charge 8.5 u C is kept at origin. Magnitude of strength of field at (4m, 3m) is [
a) 3.06 x 103 N/c b) 2.1 x 103 N/c c) 4.52 x 103 N/c d) 2.59 x 103 N/c
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Answer 1

The answer will be (A) 3.06×10^(3) N/C.

Answer 2

Answer:

The electric field value is - 3.06 × $10^{3}$ N/c i.e. option (a) is correct.

Explanation:

As we know the formula for finding electric field due to a point charge is-   E = $\frac{kq}{r^{2} }$

where    E= electric field due to point charge

              k= electrostatic constant ( 9 × $10^{9}$ )

              q= point charge

               r= distance of the charge placed

So, according to the question

   q =  8.5μC i.e. 8.5 × $10^{-6}$ C

    r =   5 (through Pythagoras theorem)

 Substituting the values in the formula -    E = 9 × $10^{9}$ × 8.5×$10^{-6}$/25

After solving we will get 3.06 × $10^{3}$ N/C

So, the correct answer is option (A).