Question

a point charge is far from all other charges at a distance of 2m from q the electric field is 20 what is the force 5 charge coulomb feel​

Answer 1

Given :

Electric field intensity at a point 2m from a point charge is 400N/C.

Tofind :

If a charge of 20 micro coulomb is placed at that point, it will experience a force of how much?

Theory:

Electric Field Intensity :

Electric field intensity at a point due to a Given charge is defined as force experienced by a unit positive charge placed at that point.

${\purple{\boxed{\large{\bold{\sf\:\vec{E}=\lim_{q_{o}\to0}\frac{\vec{F}}{q_{o}}}}}}}$

Solution:

$\implies\:\vec{E}=400\:NC{}^{-1}$

⇒r = distance from point charge =2m

Now a charge of 20μC is placed at that point .

We have to find force experienced by it .

$\bf\:\vec{F}=q\vec{E}$

$\implies\:\sf\:\vec{F}=20\times10{}^{-6}\times400$

$\implies\:\sf\:\vec{F}=20\times10{}^{-6}\times400$

$\implies\:\sf\:\vec{F}=8\times10{}^{-6}\times10{}^{3}$

$\implies\:\sf\:\vec{F}=8\times10{}^{-3}\:N$

Therefore, it will experience

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MoreAboutElectric Field

1) The SI unit of electric field is N/C or volt/meter .

Electric field intensity at a point 2m from a point charge is 400N/C

2)It is a vector quantity and it's direction is the same as force on the positive test charge .