a point charge is far from all other charges at a distance of 2m from q the electric field is 20 what is the force 5 charge coulomb feel
Answers
Answer:
Given :
Electric field intensity at a point 2m from a point charge is 400N/C.
Tofind :
If a charge of 20 micro coulomb is placed at that point, it will experience a force of how much?
Theory:
Electric Field Intensity :
Electric field intensity at a point due to a Given charge is defined as force experienced by a unit positive charge placed at that point.
{\purple{\boxed{\large{\bold{\sf\:\vec{E}=\lim_{q_{o}\to0}\frac{\vec{F}}{q_{o}}}}}}}
E
=
q
o
→0
lim
q
o
F
Solution:
\implies\:\vec{E}=400\:NC{}^{-1}⟹
E
=400NC
−1
⇒r = distance from point charge =2m
Now a charge of 20μC is placed at that point .
We have to find force experienced by it .
\bf\:\vec{F}=q\vec{E}
F
=q
E
\implies\:\sf\:\vec{F}=20\times10{}^{-6}\times400⟹
F
=20×10
−6
×400
\implies\:\sf\:\vec{F}=20\times10{}^{-6}\times400⟹
F
=20×10
−6
×400
\implies\:\sf\:\vec{F}=8\times10{}^{-6}\times10{}^{3}⟹
F
=8×10
−6
×10
3
\implies\:\sf\:\vec{F}=8\times10{}^{-3}\:N⟹
F
=8×10
−3
N
Therefore, it will experience
_____________________________
MoreAboutElectric Field
1) The SI unit of electric field is N/C or volt/meter .
Electric field intensity at a point 2m from a point charge is 400N/C
2)It is a vector quantity and it's direction is the same as force on the positive test charge .