Physics, asked by REDDY1799, 10 months ago

A point charge moving with velocity v (3m/s) i is released in a uniform electric field
+6 The subsequent trajectory of the particle will be
0
(A) A parabola
(B) An ellipse
0
(C) A rectangular hyperbola
(D) A straight line
91
97
A
103
B
109​

Answers

Answered by rakeshpilania59662
0

Answer:

(A) A parabola

(B) An ellipse

0

(C) A rectangular hyperbola

(D) A straight line

91

97

A

103

B

109

Answered by ansiyamundol2
0

Answer:

The trajectory of the particle will be Option D : A straight line.

Explanation:

Since the point charge is released in a uniform electric field and it isn't mentioned anywhere about magnetic field, it'll travel in a straight line with no disruptions.

If these was a magnetic field present, it would have travelled in helix.

Therefore, the answer is - it would travel in a straight line.

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