Question

A point charge of 0.5C is taken from point A to B as
shown in the diagram, where some equipotential
surface are drawn. The work done by the electric field
is
10 V
B
20 V
A
30 V
40 V
(A) 5J​

Answer 1

Answer:

10v

hope it's help you!!!

Answer 2

Answer:

(A) 10 J

Explanation:

Given: Charge, $q=0.5 c$

Find: Work done, $W= ?$

In the given diagram, equipotential surfaces are shown. The potential at every point on the equipotential surface is the same.

Therefore, potential at points A and B are:

$V_{A}=40 \mathrm{~V} \text { and } V_{B}=20 \mathrm{~V}$

Work done is given by the relation:

$W=q \Delta V=q\left(V_{A}-V_{B}\right)=0.5 \times(40-20)=10 J$

Hence, the work done by the electric field is 10 J.

Therefore, option (A) is correct.