A point-charge of 1.8 uC is at the centre of a cubical
Gaussian surface of 55 cm side. Find the net electric
flux through the surface. Ans. 2.0 x 105 N-mºc-1. solve
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Explanation:
We can use the following equation to figure out the net electric flux.
\Phi=\dfrac{q}{\epsilon_0}Φ=
ϵ
0
q
(Where \PhiΦ is the net flux, \epsilon_0ϵ
0
is permittivity of free space and qq is the charge enclosed)
\Phi=\dfrac{1.8\times10^{-6}}{8.85\times10^{-12}}Φ=
8.85×10
−12
1.8×10
−6
\Phi=2.034\times10^{5}Φ=2.034×10
5
\dfrac{N\cdot m^2}{C}
C
N⋅m
2
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