Question

A point charge of 10^-7 coloumb is situated at center of cube of 1m side.calculate electric flux through its surface

Answer 1

your answer is above..hope it helpes..

Answer 2

Answer:

The electric flux through its surface is $1.88\times10^{3}\ Nm^2\ C^{-1}$

Explanation:

Given that,

Charge $q = 10^{-7}\ C$

Side = 1 m

Cube has a six equal phase.

So, the electric flux through surface of cube is $6\phi$.

Where, $\phi$ is the flux through each face

According to Gauss's law

$6\phi = \dfrac{q}{\epsilon_{0}}$

$\phi=\dfrac{q}{6\epsilon_{0}}$

$\phi=\dfrac{10^{-7}}{6\times8.85\times10^{-12}}$

$\phi=1.88\times10^{3}\ Nm^2\ C^{-1}$

Hence,  The electric flux through its surface is $1.88\times10^{3}\ Nm^2\ C^{-1}$