Question

A point charge of 10 microcoulomb is placed at a distance 20cm from another identical charge 10 microcoloumb a point charge of_2 micro coulomb is moved from a to b calculate the change in potential energy of the system

Answer 1

Answer:

goooooooooooooooooooogle

Answer 2

The change in potential energy of the system is 45 J.

Explanation:

Charge 1, $q_1=10\ \mu C=10\time 10^{-6}\ C=10^{-7}\ C$

Charge 2, $q_2=10^{-7]\ C$

These two charges are placed at a distance of 20 cm form each other. We need to find the change in potential energy of the system. It is given by :

$P=\dfrac{kq_1q_2}{r^2}\\\\P=\dfrac{9\times 10^9\times 10\times 10^{-6}\times 10\times 10^{-6}}{(0.02)}\\\\P=45\ J$

So, the change in potential energy of the system is 45 J.

Learn more,

Potential energy

https://brainly.in/question/11089779