Question

A point charge of 10uC and -5uC are separated by 1M in the air the
ratio of force Exerted by one on the other?​

Answer 1

Answer:

Hello mate.

Explanation:

What is the force between two small charged spheres having charges of 2 x 10-7 C and 3 x 10-7 C placed 30 cm apart in air? Hence, force between the two small charged spheres is 6 × 10 - 3 N. The charges are of same nature. Hence, force between them will be repulsive.

Answer 2

Answer:

The ratio will be 1:1.

Explanation:

F = k*q*q₀ /r²

F₁ =  9*10⁹ * 10*10⁻⁶*5*10⁻⁶ / 1²

F₂ = 9*10⁹ * 5*10⁻⁶ *10*10⁻⁶ / 1²

The magnitudes are equal.

So, F₁/F₂ = F₂/F₁ = 1:1.

Please mark my answer as BRAINLIEST!!