A point-charge of -2 µC is placed at a distance of 2 m from another point-charge of 3 uC in air. Find the magnitude and direction of electric field at a point which is situated at a distance of 1 m from both these charges
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Answer:
Using formula, E=
4πε
o
1
r
2
q
Here, q=5×10
−6
C
r=30m
So, E=9×10
9
×
(30)
2
5×10
−6
=5×10
3
×10
−2
=5×10=50NC
−1
Explanation:
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