Physics, asked by julieanah14567, 9 months ago

A point charge of 2 mC moves from point P to point S along the path PQRS in a uniform electric field of 3 × 106 N C–1, as shown in the figure. The co-ordinates of points P, Q, R and S are (0, 0, 0), (1, –1, 0), (2, 0, 0) and (1, 1, 0) respectively. The work done (in J) by the electric field in the process is

Answers

Answered by manojdubey604
2

Answer:

Work done

E

is independent of path.

W

PQRS

=W

PS

=q[E

x

d

x

+E

y

d

y

+E

z

d

z

]=q[E(−a)+0+0]=−qEa

Negative sign here shows that work has been done against field.

Explanation:

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