Question

a point charge of -2micro coulomb is placed at a distance of 2m from another point charge of 3micro coulomb in air. find the magnitude and direction of electric field at a point which is situated at a distance of 1m from both these charge.

Answer 1

magnitude of force

equals kq1q2/r^2

q1 equals charge of first point charge
q2 equals charge of second point charge
r equals distance between them
k is electrical constant to balance out the equation
direction can be found by calculating the unit vector from assuming a direction of flow from higher charged to lower charged body

Answer 2

Answer:

hope tis might help you