Question

a point charge of 3.12e-6C is 12.3cm distant from a second point charge of -1.48e-6C. calculate the magnitude of force on each charge.

Answer 1

The magnitude of force on each charge is 2.74 N.

Explanation:

We are given that,

Charge 1, $q_1=3.12\times 10^{-6}\ C$

Charge 2, $q_2=-1.48\times 10^{-6}\ C$

Distance between charges, d = 12.3 cm

It is required to find the magnitude of force on each charge. We know that the force between two charges is given by :

$F=\dfrac{kq_1q_2}{d^2}\\\\F=\dfrac{9\times 10^9\times 3.12\times 10^{-6}\times 1.48\times 10^{-6}}{(12.3\times 10^{-2})^2}\\\\F=2.74\ N$

So, the magnitude of force on each charge is 2.74 N.

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