Question

A point charge of 3 microcoulomb is placed inside the cube of 2 cm find the electric fluxa point charge of 3 microcoulomb is placed inside the cube of 2 cm find the electric flux inside the whole cube and each face of cube ​

Answer 1

Explanation:

Total flux inside the cube is

$= \frac{q}{8.8 \times {10}^{ - 12} }$

$= \frac{3 \times {10}^{ - 6} }{8.8 \times {10}^{ - 12} }$

$= 3.409 \times {10}^{5}$

Now,

Flux through each face of cube

$= \frac{3.409 \times {10}^{5} }{6} \\ = 6.01 \times {10}^{4}$

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Answer 2

Answer:

The flux through each face of the cube $&=6.01 \times 10^{4}$.

Explanation:

The total number of electric field lines passing a given area in a unit of time exists described as the electric flux.

The SI base unit of electric flux exists voltmeters (V m).

Electric flux depends on the following factors:

• The electric field through the area
• The surface area of the area element
• The angle of inclination between the field and normal to the area element.

The total flux inside the cube is

Ф total flux of cube

$= \frac{q}{\epsilon_{0}}$

$=\frac{q}{8.8 \times 10^{-12}}$

$&=\frac{3 \times 10^{-6}}{8.8 \times 10^{-12}}$

$=3.409 \times 10^{5}$

Now,

Flux through each face of the cube

Ф flux through each face  

$= \frac{q}{6\epsilon_{0}}$

$&=\frac{3.409 \times 10^{5}}{6}$

$&=6.01 \times 10^{4}$

The flux through each face of the cube $&=6.01 \times 10^{4}$.

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