A point charge of 4.0 µC is placed at a distance of 0.10 m from a hard rubber rod with an electric field of 1.0 × 103 . What is the electric potential energy of the point charge?
× 10–4 J
What is the electric potential energy of the point charge at 1.3 m?
× 10–3 J
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Answer:
E = electric field = 1 x 10³ N/C
q = charge = 4 x 10⁻⁶ C
d = distance = 0.10 m
electric potential energy is given as
U = q E d
inserting the above values
U = (4 x 10⁻⁶ ) (1 x 10³) (0.1)
U = 4 x 10⁻⁴ J
when distance = d = 1.3 m
electric potential energy is given as
U = q E d
inserting the above values
U = (4 x 10⁻⁶ ) (1 x 10³) (1.3)
U = 5.2 x 10⁻³ J
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