Question

A point charge of magnitude 8.85×10^-2​

Answer 1

Explanation:

b) 1/6 N-M²/C

Hope it will be helpful to you....

Answer 2

Given : a point charge of magnitude 8.85x10^-12C is placed at the centre of a cube.

To find : The electric flux passing through one face.

solution : From Gauss law, electric flux through the Gaussian surface is the ratio of charge enclosed the surface to the permittivity of medium. i.e., Φ = Q/ε

here a point charge is placed at the centre of a cube ( Gaussian surface).

so, Total electric flux passing through the cube, Φ = q/ε

here, q = 8.85 × 10¯¹² C, ε = 8.85 × 10¯¹² C²/Nm²

so, Φ = (8.85 × 10¯¹² C)/(8.85 × 10¯¹² C²/Nm²)

= 1 Nm²/C

as it is being shared by six faces of cube.

so, flux passing through each face of cube = Φ/6

= 1/6 Nm²/C

Therefore The electric flux passing through one face is 1/6 Nm²/C.