Physics, asked by MuhammadTahaAli, 4 months ago

A point charge of
 {1 \times 10}^{ - 6} c
is at centre of Gaussian surface with cubical shape 1m on edge. Find flux through surface?​

Answers

Answered by pitamberpatel1678
0

Explanation:

ANSWER

(a) Electric flux, ϕ=−1×10

3

Nm

2

/C

Radius of the Gaussian surface,

r=10.0cm

Electric flux coming out through a surface depends on the net charge enclosed inside a body. It does not depend on the size of the body. If the radius of the Gaussian surface is doubled, then the flux passing through the surface remains the same i.e., - 10

3

Nm

2

/C.

(b) q=ϵ

0

Φ=8.85×10

−12

×−1×10

3

C=−8.85nC

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