Question

A point charge produces an electric flux of -750 Nm2 c-1 through a spherical gaussian surface of 10cm radius with centre at the charge if radius of gaussian surface be doulbed how much flux would pass trough the surface .? What is the magnitude of the point charge?

Answer 1

from Gauss theorem, electric flux through the gaussian surface is the ratio of charge enclosed inside the gaussian surface to the permittivity of medium.

i.e., $\textbf{Electric flux}=\frac{Q_{en}}{\epsilon_0}$

here it is clear that electric flux doesn't depend on shape and size of gaussian surface.

so, if the radius of gaussian surface is doubled. electric flux remains same. i.e., 750 Nm²/C

electric flux = 750 = $\frac{Q}{\epsilon_0}$

or, 750 = Q/8.85 × 10^-12

or, Q = 750 × 8.85 × 10^-12 C

= 6637.5 × 10^-12 C

= 6.637 × 10^-9C

Answer 2

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