Question

A point charge q =1C and mass 1kg is projected with speed u=10m/s along y direction. Uniform electric field E =100V/m is along x direction. The equation of trajectory of the particle is.

Answer 1

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Answer 2

Answer:

$y^{2} = 2x$  [Equation of trajectory of the particle]

Explanation:

Here, Charge(q)=1C , Mass(m) = 1 kg

Speed(u) = 10 m/s , Electric Field(E) = 100 V/m

Equation of motion along Y-direction:

    y = ut = 10t [t=Time] → t = $\frac{y}{10}$          ..............(i)

Equation of motion along x-direction:

   x = $\frac{1}{2} at^{2}$ = $\frac{1}{2}$ * 100 * $(\frac{y}{10})^2$ = $\frac{y^{2} }{2}$   [Where,

                                              Force(F) = ma = qE  → a = $\frac{qE}{m}$ = (1 x 100)/1 =100 N ]

    → $y^{2} = 2x$  [Equation of trajectory of the particle]