Question

A point charge Q is held fixed at origin. A second point charge -q having mass m is placed on the X-axis, at (21,0)form the origin. The second point charge is released from rest, its speed when it is at (,0) from the origin is the value of 47€om/ N= NQq


please do it fastly!!!! ​

Answer 1

Explanation:

initial energy of system =

4πϵ

1

1

q

1

q

2

when q

1

reached x=0.5, energy of system =

4πϵ

1

0.5

q

1

q

2

+

2

1

mv

2

equating the two energy,

4πϵ

1

q

1

q

2

(

1

1

−

0.5

1

)=

2

1

please mark me the brainliest

mv

2

⇒v=18.9m/s