Question

A point charge q is kept inside a conducting shell of radius 2R at a distance of R from center. Magnitude of field due to induced charges on the inner surface of the shell at point P is​

Answer 1

Answer:

a point charge q is kept I am type writer

Answer 2

Answer:

The correct answer is option A

Explanation:

There are three types of charges contributing to the field at point P

• The charge q itself
• The induced charge on the inside of the sphere
• The induced charge on the outside of the sphere.
• First, the contribution due to the charge q itself will have a magnitude of $\frac{kq}{r^2}=\frac{kq}{(4R)^2+(1R)^2} \\ =\frac{kq}{17R^2}$

Second, the field due to the induced charge on the inside of the sphere will cancel the field of the original charge and therefore have a magnitude which is equal but opposite to the field of the original charge.

Third, if the sphere is uncharged, i.e. electrically neutral, the accumulation of charge on the inside surface, will lead to an equally large, but opposite accumulation of charge on the outside surface. This charge will be evenly spread over the surface of the sphere. The magnitude of this field is $\frac{kq}{r^2} =\frac{kq}{16R^2}$

Reference Link

• https://brainly.in/question/43170016
• https://brainly.in/question/18045127
• https://brainly.in/question/14628939