a point charge +q is moved inside a spherical shell of radius R.and carrying a charge Q from a pointcharge A to another point B which is diametrically opposite. what is the work done in moving the charge from A to B. give reason?
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The charge of spherical shell is given as Q.
The radius of spherical shell is given as R.
As per the question,the point charge is present inside the shell.
The potential of spherical shell remains constant on the surface as well as inside the spherical shell.
The charge q is taken from point A to point B which are diametrically opposite.
The two points are in same potential. Hence the potential difference between them is zero.
The work done by a charge particle is calculated as -
W = V×q [Here V is the potential difference]
= 0×q
= 0 [ans]
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