Physics, asked by tejasatyasai9874, 11 months ago

A point charge q is placed at a distance a//2 directly above the centre of a square of side a. The electric flux through the square is

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Answered by ksonakshi70
4

Answer:

We imagine the face of the square as a face of a cube with edge a and charge q placed at the centre

symmetry of 6 faces of the cube about its centre ensures that electric flux (Es) same

electric flux = 6×Es

= q/6£o

= 1/6×q×a ×4×22/7×9×10^9

Answered by Anonymous
0

Answer:

Hey mate your answer is given below

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