Question

A point charge q is placed at a distance a/2 directly above the centre of a square of side a. The electric flux through the square is

Answer 1

Answer:

D oq÷6(epsilon not)

Explanation:

construct a cube of side a.now place the point charge at the centre of the cube,now each surface of the cube is placed equidistant from the charge. flux means the number of Electric field lines passing through the total surface area.

by Gauss law electric flux is Q(charge enclosed)÷epsilon not. the flux through the cube is Q÷epsilon not.each side is kept equidistant from the charge so the flux through each side is same. let flux through one side is x.

then 6x=Q÷epsilon not.

then flux through one side is Q÷6(epsilon not)

hlo clarified if not I will solve it on paper and I will post pic.