A point charge +q is placed at a distance d from an isolated conducting plane. The field at a point p on the other side of the plane is directed perpendicular to the plane and away from the plane. why is this so???
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Hey friend , this is occur in image method problem
i.e when any problem which is difficult to solve by gauss method , then we try to solve by the help of laplace or possion equation ,but by the help of laplace and possion equation it is too length process.
In case of isolated conducting plane or infinite potential and e=0, v=0, plane we use image method,
By this method we can be easily solve problem by using a imaginary charge which is perpendicular to the plane and also be opposite side , and same length from the plane ,
The aim to do this is that ,balance the effect of charge on plane
this methid is easy to solve ,
use can be read this like problem in any standard electrostatic books or any other sources which u like
the name of this method is image charge method.
mark me as brainliest
i.e when any problem which is difficult to solve by gauss method , then we try to solve by the help of laplace or possion equation ,but by the help of laplace and possion equation it is too length process.
In case of isolated conducting plane or infinite potential and e=0, v=0, plane we use image method,
By this method we can be easily solve problem by using a imaginary charge which is perpendicular to the plane and also be opposite side , and same length from the plane ,
The aim to do this is that ,balance the effect of charge on plane
this methid is easy to solve ,
use can be read this like problem in any standard electrostatic books or any other sources which u like
the name of this method is image charge method.
mark me as brainliest
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