Physics, asked by brajes99, 3 months ago

A point charge Q is placed in uniform electric field Ē=Ei+Ej at position (a.
b). Find work done in moving it to position (c. d):​

Answers

Answered by kartikrajput33556677
0

Answer:

Iron surface is coated with paint. ... The iron surface is shielded from oxygen and moisture. b) Iron is coated with another metal such as zinc. The process is called galvanising.

Answered by talasilavijaya
1

Answer:

The work done in moving a charge from position (a. b) to (c. d) is \big[-Q\big(E(c-a)+E(d-b)\big)\big]~J

Explanation:

Given a point charge Q is placed in uniform electric field \vec E=E\hat i+E\hat j

Charge is moved from position (a. b) to position (c. d)

Work done in moving a charge from one point to the another is given by

W_{A\rightarrow B} =-Q\int\limits^{B}_{A} {\vec E.d\vec r}

Then work done in moving a charge from (a. b) to  (c. d) is

W=-Q\int\limits^{c,d}_{a,b} {(E\hat i+E\hat j).(dx\hat i+dy\hat j)}

=-Q\int\limits^{c,d}_{a,b} {(Edx+Edy)

=-Q(Ex+Ey)\Big|\limits^{c,d}_{a,b}

=-Q\big(E(c-a)+E(d-b)\big)

Therefore, the work done in moving a charge from position (a. b) to position (c. d) is \big[-Q\big(E(c-a)+E(d-b)\big)\big]~J

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