Physics, asked by rajveer591, 11 months ago

A point charge q moves from point P to point S
along the path PQRS (figure) in a uniform electric
field E pointing parallel to the positive direction of
the X-axis. The co-ordinates of the points P,Q,R and
S are (a, b, 0), (2a, 0, 0), (a, b, 0) and
(0, 0, 0) respectively. The work done by the field
in the above process is :-
Y
o sicolo
hon
|
P
SADE
(1) qEa
(3) qEav 2
Ř
tuol (2) qEa
(4) qE/(2a)2 + b?]​

Answers

Answered by cityplus80
3

Answer:

i hope this ans please ans

Answered by ishikakumari822
6

Answer:-qEa

Explanation:

Work done by the electric field is independent of the path.

W(pqrs)= W(ps)

=q(Ex dx+ Ey dy+Ez dz)

=q[E(-a)+0+0]

=-qEa

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