Question

A point charge qA = 2µc is placed at point 'A' (3, 3) another charge qB = 3µc is placed at point B (2, 5) if distances are in SI units find electrostatics force on 'A' due to 'B' :-

Answer 1

Answer:

(a) The situation is represented in the given figure. O is the mid-point of line AB.



Distance between the two charges, AB=20cm

∴AO=OB=10cm

Net electric field at point O=E

Electric field at point O caused by +3 C charge,

E1=4π∈0(AO)23×10−6=4π∈0(10×10−2)23×10−6N/C along OB

Where,

∈0= Permittivity of free space

4π∈01=9×109Nm2C−2

Magnitude of electric field at point O caused by - 3 C charge,

E2=∣∣∣∣∣4π∈0(OB)2−3×10−6∣∣∣∣∣=4π∈0(10×10−2)23×10−6N/C along OB

∴