a point D is taken on the side BC of a trriangle ABC such that BD=2DC. prove that area of triangle ABD=area of triangle ADC.
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as BD = 2CD
BD = CD
THUS JOINING POINT A AND POINT D FORMS THE MEDIAN OF THE TRIANGLE JOINING THE SIDE BC.
THEREFORE ARE A OF TRIANGLE ABD = AREA OF TRIANGLE ACD.
BD = CD
THUS JOINING POINT A AND POINT D FORMS THE MEDIAN OF THE TRIANGLE JOINING THE SIDE BC.
THEREFORE ARE A OF TRIANGLE ABD = AREA OF TRIANGLE ACD.
dhruvsh1:
sorry i will send it again it went wrong
hey friend i think that the question might be bd = 2bc
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