Question

A point E is taken on the side CD of a parallelogram ABCD and CD is produced to F, so that
DF = CE. BE produced meets AD produced in G and the line through F parallel to AG in H.
Prove that parallelogram AFHG = parallelogram ABCD. The area of parallelogram AFHG is
equal to the area of parallelogram ABCD.​

Answer 1

Answer:

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