Question

a point in the 2nd quadrant is at a distance of 3 units from the x axis and 4 units from the y axis. its distance from (1.2) is

Answer 1

Answer:

6.003

(considering the point 1.2 is in the 1st quadrant and in the x-axis only)

Step-by-step explanation:

1. Marking the 1st point which is at 3 units apart from x axis and 4 units apart from y axis.
2. Assuming 1.2 is in the 1st quadrant with solely on x axis.
3. Also assuming the distance taken is linear from both points.
4. From the above diagram you can observe, the lines which forms resembles like a Right Angle Triangle.
5. So by simply using Pythagoras Theorem you will get the required answer.

Bonus trick

you can also use a simple formula instead of this,

Distance between two points is:

$\sqrt{(x1 - x2)^{2} + (y1 - y2)^{2} }$

here,

x1 and x2 are the x co-ordinates of both the points

and

y1 and y2 are the y co-ordinates of both the points

you can use both the methods will give you same answer.

hope you like this answers. If you have any doubt just feel free to messege me.

Answer 2

Answer:

6.003

(considering the point 1.2 is in the 1st quadrant and in the x-axis only)

Step-by-step explanation:

Marking the 1st point which is at 3 units apart from x axis and 4 units apart from y axis.

Assuming 1.2 is in the 1st quadrant with solely on x axis.

Also assuming the distance taken is linear from both points.

From the above diagram you can observe, the lines which forms resembles like a Right Angle Triangle.

So by simply using Pythagoras Theorem you will get the required answer.

Bonus trick

you can also use a simple formula instead of this,

Distance between two points is:

\sqrt{(x1 - x2)^{2} + (y1 - y2)^{2} }

(x1−x2)

2

+(y1−y2)

2

here,

x1 and x2 are the x co-ordinates of both the points

and

y1 and y2 are the y co-ordinates of both the points

you can use both the methods will give you same answer.

hope you like this answers. If you have any doubt just feel free to messege me.